
How can you quickly know if one number will
divide evenly into another number, leaving no remainder? For example, will 3
divide evenly into 2,169,252? Well, I wouldn't have brought the subject up if I
didn't know some curious shortcuts...
Division by 2
No surprise here. Any number that ends in 0,2,4,6 or 8 is evenly divisible
by 2.
Division by 3
Add the number's digits. If the sum is evenly divisible by 3, then so is the
number. So, will 3 divide evenly into 2,169,252? Yes it will, because the sum of
the digits is 27, and 27 is divisble by 3. If you want, you can keep adding
numbers until one digit remains. For example, keep going with 27. 2 + 7 = 9,
which is also evenly divisible by 3.
Division by 4
If the number's last 2 digits are 00 or if they form a 2-digit number evenly
divisible by 4, then number itself is divisible by 4. How about 56,789,000,000?
Last 2 digits are 00, so it's divisible by 4. Try 786,565,544. Last 2 digits,
44, are divisible by 4 so, yes, the whole number is divisible by 4.
Division by 5
Any number that ends in a 0 or 5 is evenly divisible by 5. Easy enough.
Division by 6
The number has to be even. If it's not, forget it. Otherwise, add up the
digits and see if the sum is evenly divisible by 3. It it is, the number is
evenly divisible by 6. Try 108,273,288. The digits sum to 39 which divides
evenly into 13 by 3, so the number is evenly divisible by 6. If you want, you
can keep adding numbers until only one digit remains and do the same thing. So
in this case, 3 + 9 = 12 and 1 + 2 = 3, and 3 is evenly divisible by 3!
Division by 7
Multiply the last digit by 2. Subtract this answer from the remaining
digits. Is this number evenly divisible by 7? If it is, then your original
number is evenly divisible by 7. Try 364. 4, the last digit, multiplied by 2 =
8. 36, the remaining digits, minus 8 = 28. The last time I checked, 28 is evenly
divisble by 7, and thus, so is 364!
Division by 8
If the number's last 3 digits are 000 or if they form a 3-digit number
evenly divisible by 8, then the number itself is divisible by 8. How about
56,789,000,000? Last 3 digits are 000, so it's divisible by 8. Try 786,565,120.
The last 3 digits, 120, divide by 8 into 15, so yes, the whole number is
divisible by 8.
Division by 9
Sum the number's digits. If it divides by 9, you're in luck. As with the
tests for 3 and 6, you can keep adding numbers until you're left with only one
digit.
Division by 10
Any number that ends in 0 is evenly divisible by 10.
Division by 11
Here are four ways for different types of numbers:
Division by 12
If the number can be evenly divided by 3 and 4, the same can also be said
for 12. Use the methods for Division by 3 and Division by 4 above. If they both
work, your number is also evenly divisible by 12.
Division by 15
If the number can be evenly divided by 3 and 5, the same can also be said
for 15. Use the methods for Division by 3 and Division by 5 above. If they both
work, your number is also evenly divisible by 15.
Division by 24
If the number can be evenly divided by 3 and 8, the same can also be said
for 24. Use the methods for Division by 3 and Division by 8 above. If they both
work, your number is also evenly divisible by 24.
Division by 33
If the number can be evenly divided by 3 and 11, the same can also be said
for 33. Use the methods for Division by 3 and Division by 11 above. If they both
work, your number is also evenly divisible by 33.
Division by 36
If the number can be evenly divided by 4 and 9, the same can also be said
for 36. Use the methods for Division by 4 and Division by 9 above. If they both
work, your number is also evenly divisible by 36.
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